Show that $x+2$ is a factor of $$2x^3-x^2-13x-6$$ and hence fully factorise it.
Factor theorem with $x = -2$, $(x+2)(x-3)(2x+1)$
Solve algebraically, showing each step of your working, the equation $$(8^{x-1})^2-18(8^{x-1})+32=0$$
Use substitution $y = 8^{x-1}$ to get $x = \dfrac{7}{3}$ or $x = \dfrac{4}{3}$